Question

Thực hiện phép tính một cách hợp lí: 

1) \(A=\frac{636363\cdot37-373737\cdot63}{1+2+3+...+2006}\)

2)\(B=1\frac{6}{41}\cdot\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{1}{3}-\frac{3}{37}-\frac{3}{53}}:\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}\right)\cdot\frac{124242423}{237373735}\)

Answer 1

Mình nghĩ đề thế này mới tính hợp lí được

2 ) B = \(1\frac{6}{41}.\left(\frac{12+\frac{12}{19}-\frac{12}{37}-\frac{12}{53}}{3+\frac{3}{19}-\frac{3}{37}-\frac{3}{53}}:\frac{4+\frac{4}{17}+\frac{4}{19}+\frac{4}{2006}}{5+\frac{5}{17}+\frac{5}{19}+\frac{5}{2006}}\right).\frac{124242423}{237373735}\)

B = 47/41 . ( 12/3 : 4/5 ) . 123/235

B = 47/41 . ( 4 : 4/5 ) . 123/235

B = 47/41 . 5 . 123/235

B = \(\frac{47.5.123}{41.235}\)

B = 3

Answer 2

1 ) A = \(\frac{636363.37-373737.63}{1+2+3+...+2006}\)

A = \(\frac{63.10101.37-37.10101.63}{1+2+3+...+2006}\)

A = \(\frac{0}{1+2+3+...+2006}\)

A = 0