a) 45.37 + 45.63 - 100
\( 45.(37 + 63) – 100 \)
\(45.100 – 100\)
\(100.(45 – 1) \)
\( 100 . 44 = 4400\)
a)\(=45.\left(37+63-\dfrac{20}{9}\right)=45\cdot\dfrac{880}{9}=4400\)
b)\(=148.9-9.48=9.\left(148-48\right)=9.100=900\)
\(148.9 - 3^2.48\)
\(= 148.9 – 9.48 \)
\(= 9.(148 – 48)\)
\(= 9.100 = 900\)
\(307 - [(180.4^0 - 160) : 2^2 + 9] : 2 \)
= \(307 – [(180.1 – 160):4 + 9]:2\)
=\(307 – [20:4 + 9]:2 \)
= \(307 – [5 + 9]:2\)
= \(307 – 14:2\)
=\( 307 – 7 = 300\)
Lời giải:
a. $=45(37+63)-100=45.100-100=100(45-1)=100.44=4400$
b. $=148.9-9.48=9(148-48)=9.100=900$
c. $=307-[(180-160):4+9]:2=307-(20:4+9):2=307-14:2=307-7=300$
d. \(=12+3.90:[39-(8-5)^2]=12+3.90:(39-9)=12+3.90:30=12+3.3=12+9=21\)