Question

Thực hiện phép tính 

a) x+1 phần 5 - 2 phần x 

b) x+y phần 9x : x+y phần 3x 

Answer 1

\(a,\dfrac{x+1}{5}-\dfrac{2}{x}\)

\(=\dfrac{x\left(x+1\right)-2.5}{5x}=\dfrac{x^2+x-10}{5x}\)

\(b,\dfrac{x+y}{9x}:\dfrac{x+y}{3x}\)

\(=\dfrac{x+y}{9x}.\dfrac{3x}{x+y}=\dfrac{1}{3}\)

Answer 2

a. \(\dfrac{x+1}{5}\)-\(\dfrac{2}{x}\)=\(\dfrac{x\left(x+1\right)-2.5}{5x}\)=\(\dfrac{x^2+x-10}{5x}\)

b. \(\dfrac{x+y}{9x}:\dfrac{x+y}{3x}\)=\(\dfrac{x+y}{9x}.\dfrac{3x}{x+y}=\dfrac{1}{3}\)