Question

Thực hiện phép tính :      9.\(\left(\frac{-1}{3}\right)^3-3.\left(\frac{-1}{3}\right)^2+2.\left(\frac{-1}{3}\right)+1\)

Answer 1

= 9 x -1/27 - 3 x 1/9 + 2 x -1/3 + 1 

= -1/3 - 1/3 + -2/3 + 1 

= -1/3

Answer 2

\(9\left(\frac{-1}{3}\right)^3-3.\left(-\frac{1}{3}\right)^2+2.\left(-\frac{1}{3}\right)+1\)

\(=\frac{-9}{27}-\frac{-3}{9}+\frac{-2}{3}+1\)

\(=-\frac{1}{3}-\frac{-1}{3}+\frac{-2}{3}+1\)

\(=-\frac{1}{3}\)