\(\left(2^2\times3\right)^8:\left(8^5\times9^4\right)\)
\(=\left[\left(2^2\right)^8:3^8\right]:\left[\left(2^3\right)^5\times\left(3^2\right)^4\right]\)
\(=\left(2^{16}\times3^8\right):\left(2^{15}\times3^8\right)\)
\(=\frac{2^{16}\times3^8}{2^{15}\times3^8}=\frac{2^{16}}{2^{15}}=2\)