Giải các phương trình ẩn x sau:
1) \(\frac{x}{x-3}-\frac{2x^2+9}{2x^2-3x-9}\)\(=\frac{1}{2x+3}\)
2) \(\frac{x}{2x-3}+\frac{1}{x-3}=\frac{x^2-x-3}{2x^2-9x+9}\)
3) \(\frac{3}{x+2}-\frac{2x-20}{3x^2+4x-4}=\frac{7}{3x-2}\)
giúp mik vs mai mik kiểm tra rùi
a) $\frac{x-1}{x}$ - $\frac{1}{x+1}$ = $\frac{2x-1}{x2+x}$
b) (x+2).(5-3x)=0
c)$\frac{5(1-2x)}{3}$ + $\frac{x}{2}$ = $\frac{3(x-5)}{4}$ - 2
d)$(x+2)^{2}$ - (x-1).(x+3) = (2x-4).(x+4)-3
e)$(2x-3)^{2}$ = (2x-3).(x+1)
1) Giải các phương trình:
a) \(\frac{x-3}{5}-\frac{2x-1}{10}=\frac{x+1}{2}+\frac{1}{4}\)
b)\(\frac{x+3}{2}-\frac{2-1}{3}-1=\frac{x+5}{6}\)
c)\(\frac{x-1}{4}-\frac{5-2x}{9}=3x-\frac{2}{3}\)
d)\(\frac{2x-1}{4}+\frac{x-3}{3}=\frac{4x-2}{3}-\frac{6x+7}{12}\)
e)\(\frac{3x-2}{5}+\frac{x-1}{9}=\frac{14x-3}{15}-\frac{2x+1}{9}\)
Rút gọn các phân thức đại số sau:
A=\(\frac{2x}{x^2-3x}+\frac{2x}{x^2-4x+3}+\frac{x}{x-1}\)1
B=\(\frac{x}{x+2}+\frac{2}{x-2}-\frac{4x}{4-x^2}\)
C=\(\frac{1+x}{3-x}-\frac{1-2x}{3+x}-\frac{x\left(1-x\right)}{9-x^2}\)
D=\(\frac{5}{2x^2+6x}-\frac{4-3x^2}{x^2-9}-3\)
E=\(\frac{3x+2}{x^2-2x+1}-\frac{6}{x^2-1}-\frac{3x-2}{x^2+2x+1}\)
Giúp mik mấy câu này vs mik đg cần gấp mik cảm ơn mng trước😘😘
Giải phương trình:
2x-2=8-3x
x2-3x+1=x+x2
(x2+1)(2x+4)=0
(4x+1)(x2+2)=0
\(\frac{x}{2}=3-\frac{x+4}{3}\)
\(\frac{3-x}{4}=1-\frac{3x-5}{6}\)
\(\frac{2x+5}{9}=2+\frac{x-3}{6}\)
\(\frac{x+5}{3}=1+\frac{x-3}{9}\)
\(\frac{2x-5}{x+5}=3\)
\(\frac{x^2-6}{x}=x+\frac{3}{2}\)
\(\frac{\left(x^2+2x\right)-\left(3x+6\right)}{x-3}=0\)
\(\frac{5}{3x+2}=2x-1\)
\(\frac{x^2-x}{x^2-x+1}-\frac{x^2-x+2}{x^2-x-2}=1.\)
\(\frac{1}{x^2-3x+3}+\frac{2}{x^2-3x+4}=\frac{6}{x^2-3x+5}\)
\(\frac{1}{x^2-2x+2}+\frac{1}{x^2-2x+3}=\frac{9}{2\left(x^2-2x+4\right)}\)
\(\frac{1}{x^2-2x+3}+\frac{1}{x^2-2x+2}=\frac{6}{x^2-2x+4}\)
Giải các phương trình
a) \(\frac{2x}{x-1}+\frac{4}{x^2+2x-3}=\frac{2x-5}{x+3}\)
b)\(\frac{x^2-x}{x+3}-\frac{x^2}{x-3}=\frac{7x^2-3x}{9-x^2}\)
c)\(\frac{3}{4x-20}+\frac{15}{50-2x^2}+\frac{7}{6x+30}\)
Bài 4: Giải các phương trình sau
a) 4(x+5)(x+6)(x+10)(x+12)=\(3x^2\)
b) \(\frac{1}{x^2-3x+3}+\frac{2}{x^2-3x+4}=\frac{6}{x^2-3x+5}\)
c) \(\frac{4x}{4x^2-8x+7}+\frac{3x}{4x^2-10x+7}=1\)
d) \(\frac{2x}{2x^2-5x+3}+\frac{13x}{2x^2+x+3}\)