a) a - b + c - (a - b + c) + 3b
= a - b + c - a + b - c +3b
= 3b
b) - (2a - b) - (b + 3a)
= -2a + b - b - 3a
= -5a
c) a(b + c) - b(a - c)
= ab + ac - ab + bc
= ac + bc
\(a,a-b+c-\left(a-b+c\right)+3b=a-b+c-a+b-c+3b\)
\(=3b\)
\(b,-\left(2a-b\right)-\left(b+3a\right)=-2a+b-b-3a=-5a\)
\(c,a\left(b+c\right)-b\left(a-c\right)=ab+ac-ab+bc=ac+bc\)
a) a - b + c - (a - b + c) + 3b
=a - b + c - a + b - c + 3b
=3b
b) - (2a - b)-(b + 3a)
=-2a-b-b-3a
=-5a-2b
c) a(b+c) - b(a-c)
=ab+ac-ba+bc
=ac+bc
=(a+b)c