Question

Thu gọn biểu thức A = \(\frac{\frac{1}{a}+\frac{2}{b}}{a}+\frac{\frac{1}{b}+\frac{2}{c}}{b}+\frac{\frac{1}{c}+\frac{2}{a}}{c}\),biết \(a,b,c\in Z;a+b+c=0;abc\ne0\)

Answer 1

\(=\frac{1}{a^2}+\frac{2}{ab}+\frac{1}{b^2}+\frac{2}{bc}+\frac{1}{c^2}+\frac{2}{ac}\)

\(=\frac{1}{a^2}+\frac{1}{b^2}+\frac{1}{c^2}+\frac{2a+2b+2c}{abc}=\frac{1}{a^2}+\frac{1}{b^2}+\frac{1}{c^2}\)

Answer 2

\(A=\frac{1}{a^2}+\frac{2}{ab}+\frac{1}{b^2}+\frac{2}{bc}+\frac{1}{c^2}+\frac{2}{ac}=\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)^2\)

Linh không biết a + b + c = 0 để làm gì?

Answer 3

thành cũng chẳng biết nữa cơ