Question

\(\text{Phân tích đa thức thành nhân tử (bằng kĩ thuật tách hạng tử)}\):\( -8x^2 +23x + 3\)

Answer 1

Ta có: \(-8x^2+23x+3\)

\(=\left(-8x^2+24x\right)-\left(x-3\right)\)

\(=-8x\left(x-3\right)-\left(x-3\right)\)

\(=\left(-8x-1\right)\left(x-3\right)\)

\(=\left(3-x\right)\left(8x+1\right)\)

Answer 2

\(-8x^2+23x+3\)

\(=-\left(8x^2-23x-3\right)\)

\(=-\left(8x^2-24x+x-3\right)\)

\(=-\left[8x\left(x-3\right)+\left(x-3\right)\right]\)

\(=-\left(8x+1\right)\left(x-3\right)\)

Answer 3

-8x² + 23x + 3

= -8x² - x + 24x + 3

= -x( 8x + 1 ) + 3( 8x + 1 )

= ( 8x + 1 )( 3 - x )

Answer 4

\(-8x^2+23x+3\)

\(=\left(-8x^2+24x\right)-\left(x-3\right)\)

\(=-8x\left(x-3\right)-\left(x-3\right)\)

\(=\left(-8x-1\right)\left(x-3\right)\)

\(=\left(3-x\right)\left(8x+1\right)\)

Answer 5

\(-8x^2+23x+3\)

\(=-8x^2+24x-x+3\)

\(=-8x\left(x-3\right)-\left(x-3\right)\)

\(=\left(-8x-1\right)\left(x-3\right)\)

\(=\left(3-x\right)\left(8x+1\right)\)

Answer 6

            Bài làm :

Ta có:

 \(-8x^2+23x+3\)

\(=\left(-8x^2+24x\right)-\left(x-3\right)\)

\(=-8x\left(x-3\right)-\left(x-3\right)\)

\(=\left(-8x-1\right)\left(x-3\right)\)

\(=\left(3-x\right)\left(8x+1\right)\)