Lời giải:
Xét tam giác $KPL$ có:
$\widehat{PKL}+\widehat{PLK}+\widehat{LPK}=180^0$
$74^0+\widehat{PLK}+90^0=180^0$
$\widehat{PLK}=16^0$ hay $\widehat{HLM}$
Xét tam giác $HML$ có:
$\widehat{HML}+\widehat{HLM}+\widehat{LHM}=180^0$
$90^0+16^0+\widehat{LHM}=180^0$
$\widehat{LHM}=74^0$