Question

Ta có \(\frac{x-1}{x+2}\)= \(\frac{x-2}{x+3}\) 

Tính x 

-=> x = ? 

Answer 1

ta có 

\(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)

=> (x-1)(x+3)=(x+2).(x-2)

=> x²+3x-x-3=x²-4

=>x²+2x-3-x²+4=0

=>2x+1=0

=>2x=-1

=>x=-1/2

Answer 2

=>(x-1)(x+3)=(x+2)(x-2)

=>x(x+3)-1(x+3)=x(x-2)+2(x-2)

=>x^2+3x-x-3=x^2-2x+2x-4

=>x^2+2x-3=x^2-4

=>x=-1/2=-0,5

 Vậy x=-0,5