Đặt \(A=3+\frac{3}{5}+\frac{3}{25}+\frac{3}{125}+\frac{3}{625}\)
\(5A=15+3+\frac{3}{5}+\frac{3}{25}+\frac{3}{125}\)
\(5A-A=\left(15+3+\frac{3}{5}+\frac{3}{25}+\frac{3}{125}\right)-\left(3+\frac{3}{5}+\frac{3}{25}+\frac{3}{125}+\frac{3}{625}\right)\)
\(4A=15-\frac{3}{625}\)
\(A=\frac{15-\frac{3}{625}}{4}\)
Ủng hộ mk nha ^_-
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