Question

SS A và B

A=\(\frac{19}{24}-\frac{1}{2}-\frac{1}{3}-\frac{7}{24}\)

B=\(\frac{7}{24}+\frac{5}{6}+\frac{1}{4}-\frac{3}{7}-\frac{5}{15}\)

Answer 1

\(A=\frac{19}{24}-\frac{1}{2}-\frac{1}{3}-\frac{7}{24}\)

\(A=\frac{19}{24}-\frac{12}{24}-\frac{8}{24}-\frac{7}{24}\)

\(A=\frac{19-12-8-7}{24}\)

\(A=\frac{-8}{24}\)\(=\frac{-1}{3}\)

Answer 2

\(B=\frac{7}{24}+\frac{5}{6}+\frac{1}{4}-\frac{3}{7}-\frac{5}{15}\)

\(B=\frac{7}{24}+\frac{30}{24}+\frac{6}{24}-\frac{3}{7}-\frac{1}{3}\)

\(B=\frac{7}{24}+\frac{30}{24}+\frac{6}{24}-\frac{3}{7}-\frac{8}{24}\)

\(B=\frac{7+30+6-8}{24}-\frac{3}{7}\)

\(B=\frac{21}{24}-\frac{3}{7}\)

\(B=\frac{7}{8}-\frac{3}{7}\)

\(\Rightarrow B=\frac{25}{56}\)