\(\sqrt{x^2-3x+2}+\sqrt{x+3}=\sqrt{x-2}+\sqrt{x^2+2x-3}\)
<=> \(\sqrt{\left(x-1\right)\left(x-2\right)}+\sqrt{x+3}=\sqrt{x-2}+\sqrt{\left(x-1\right)\left(x+3\right)}\)
<=> (\(\sqrt{x-1}-1\))(\(\sqrt{x-2}-\sqrt{x+3}\)) = 0
<=> \(\orbr{\begin{cases}\sqrt{x-1}=1\\\sqrt{x-2}=\sqrt{x+3}\end{cases}}\)
<=> x = 2