đk x ≥ 1
+, \(\sqrt{x-1}+5=0\\ \sqrt{x-1}=-5\left(voli\right)\)
+, \(\sqrt{x}\left(\sqrt{x}-6\right)=0\\ =>\sqrt{x}=0hoac\sqrt{x}-6=0\\ =>x=0\left(thoamanđk\right);x=36\left(thoamanđk\right)\)
đk x ≥ 1
+, \(\sqrt{x-1}+5=0\\ \sqrt{x-1}=-5\left(voli\right)\)
+, \(\sqrt{x}\left(\sqrt{x}-6\right)=0\\ =>\sqrt{x}=0hoac\sqrt{x}-6=0\\ =>x=0\left(thoamanđk\right);x=36\left(thoamanđk\right)\)
\(\left(\sqrt{x}-1+5\right)\times\left(x-6\times\sqrt{x}=0\right)\)
\(\left(\sqrt{x}-1+5\right)\times\left(x-6\times\sqrt{x}\right)=0\)
tìm x biết :
a)\(2\sqrt{x}+3=0\)
b)\(\frac{5}{12}\sqrt{x}-\frac{1}{6}=\frac{1}{3}\)
c)\(\sqrt{x+3}+3=0\)
Tìm x, biết:
\(\left(\sqrt{x-1}+5\right)\left(x-6\sqrt{x}\right)=0\)
Help!
tìm x biết :
a) \(2\sqrt{x}+3=0\)
b)\(\frac{5}{12}\sqrt{x}-\frac{1}{6}=\frac{1}{3}\)
c) \(\sqrt{x+3}+3=0\)
\(1) x-5 \sqrt{x}=0 \)
\(2) 2x^7=3x^9\)
\(3) x^6 = 4x^8\)
\(4)x^4=256\)
\(5) (\sqrt{x}-1)^2=0,5625 \)
\(6) x+ \sqrt{x}=0 \)
\(7) x^2=(1^3+2^3+3^3+4^3+5^3).123454321\)
Tìm x nha
thanks nhìu
\(2\left|2x-6\right|=\dfrac{5}{6}-\left|x-3\right|\)
2:\(\left|x+2013\right|+\left|x+2014\right|+\left|x+2045\right|=2\)
3:\(\left|2x-1\right|=\left|x+1\right|\)
4:\(\sqrt{\left(x+\sqrt{5}\right)}+\sqrt{\left(y-\sqrt{3}\right)^2}+\left|x-y-z\right|=0\)
Rút gọn : A=\(\left(1-\frac{\sqrt{x}}{\sqrt{x}+1}\right):\left(\frac{2+\sqrt{x}}{x-5\sqrt{x}+6}+\frac{3+\sqrt{x}}{\sqrt{x}-2}-\frac{2+\sqrt{x}}{\sqrt{x}-3}\right)\)
Bài 1: Tìm x, biết:
a) \(\sqrt{1,69}.(2.\sqrt{x}+\sqrt{81/121})=13/10\)
b) \((2x^2-3).(3x^2-1/0,12).(x^2+1)=0\)
c) \(|2/5.\sqrt{x}-1/20|-3/4=1/5\)
d) \(x-5\sqrt{x}=0\)
e) \(2x^7=3x^9\)
f) \(x^6=4x^8\)
Giải hộ mik với nha! Thank you
a,-12:(3/4-5/6)^2
,b,10.\(\sqrt{0.01}.\sqrt{\dfrac{16}{9}+3\sqrt{49}-\dfrac{1}{6}\sqrt{4}}\)
c,x/6=y/3=z/2 và x-2y+4z=8
d,|1/4+x|-1/3=2/5