Question

\(\sqrt{\left(-7\right)}^2+\sqrt{\frac{25}{16}-\frac{3}{2}}\)

Answer 1

\(\sqrt{\left(-7\right)^2}+\sqrt{\frac{25}{16}-\frac{3}{2}}\)

\(=7+\sqrt{\frac{1}{16}}\)

\(=7+\frac{1}{4}\)

\(=7\frac{1}{4}=\frac{29}{4}\)

Answer 2

\(\sqrt{\left(-7\right)^2}\)+ \(\sqrt{\frac{25}{16}}\)

= 7 +\(\frac{5}{4}\)

= \(8\frac{1}{4}\)

=\(\frac{33}{4}\)