Các câu hỏi tương tự
Tìm x biết :
a, 4.(18 - 5x) - 12.(3x - 7) = 15.(2x - 16) - 6(x + 14)
b, 5.(3x + 5) - 4.(2x - 3) = 5x + 3.(2x + 12) + 1
c, 2.(5x - 8) - 3.(4x - 5) = 4.(3x - 4) + 11
d, (3x + 2)(2x + 9) - (x + 2)(6x + 1) = (x + 1) - (x - 6)
e, (8x - 3)(3x + 2) - (4x + 7)(x + 4)= (2x + 1)(5x - 1) - 33
Ai giải được chắc thiên tài
11 x 11 = 4
22 x 22 = 16
33 x 33 = ?
tìm x biết \(sqrt{9+5x^2}+sqrt{x^4+16}\)=7-2015x2
Tìm x biết:
a) 4(18-5x) - 12(3x-7) = 15(2x-16) - 6(x+14)
b) 5(3x+5) - 4(2x-3) = 5x+3(2x+12)+1
c)2(5x-8) - 3(4x-5) = 4(3x-4) + 11
d) 5x-3 {4x-2 [4x-3(5x-2)]}=182
Tìm x biết
\(a,-\frac{1}{2}\left(3x-1\right)+\frac{3}{4}\left(3-2x\right)=-3\left(\frac{x}{2}-1\right)-\left(\frac{4}{5}\right)^{-1}\)
\(b,\sqrt{9\left(5x-1\right)}-\sqrt{16\cdot\left(5x-1\right)}+\sqrt{36\left(5x-1\right)}=15\)
MÌNH ĐANG CẦN GẤP GIẢI CỤ THỂ GIÚP MÌNH NHA
left(-1,25right).14,7.left(-8right) frac{3}{4}-1frac{1}{6}frac{-3}{5}.51frac{11}{13}+frac{3}{5}.21frac{11}{13}|frac{-3}{4}|.|-frac{2}{3}|frac{-3}{5}+5frac{1}{13}-frac{2}{3}+1frac{3}{5}-frac{11}{33}frac{3}{4}.sqrt{16}-10.sqrt{0,81}left(frac{3}{4}right):left(-frac{3}{8}right)frac{6^4.15^3}{8.9^3.10^3}
Đọc tiếp
\(\left(-1,25\right).14,7.\left(-8\right)\)
\(\frac{3}{4}-1\frac{1}{6}\)
\(\frac{-3}{5}.51\frac{11}{13}+\frac{3}{5}.21\frac{11}{13}\)
\(|\frac{-3}{4}|.|-\frac{2}{3}|\)
\(\frac{-3}{5}+5\frac{1}{13}-\frac{2}{3}+1\frac{3}{5}-\frac{11}{33}\)
\(\frac{3}{4}.\sqrt{16}-10.\sqrt{0,81}\)
\(\left(\frac{3}{4}\right):\left(-\frac{3}{8}\right)\)
\(\frac{6^4.15^3}{8.9^3.10^3}\)
Tìm GTNN:
\(A=\sqrt{x+2,4}+\frac{4}{7}\)
\(B=\sqrt{2x+\frac{4}{11}}-\frac{16}{191}\)
\(12\frac{3}{11}-\frac{6}{13}+3,25-5\frac{3}{11}-4\frac{7}{13}+\sqrt{1\frac{9}{16}}\)
25 tháng 7 2023 lúc 10:18
Bài 1: Tìm x; y ϵ ℤ
a) 2x - ysqrt{6} 5 + (x + 1)sqrt{6}
b) 5x + y - (2x -1)sqrt{7} ysqrt{7} + 2
Bài 2: So sánh M và N
M dfrac{dfrac{3}{4}+dfrac{3}{5}+dfrac{3}{7}-dfrac{3}{11}}{dfrac{6}{4}+dfrac{6}{5}+dfrac{6}{7}-dfrac{6}{11}}
N dfrac{dfrac{2}{3}+dfrac{2}{5}-dfrac{2}{7}-dfrac{2}{11}}{dfrac{6}{2}+dfrac{6}{5}-dfrac{6}{7}-dfrac{6}{11}}
Bài 3: Chứng minh:
dfrac{1}{2!}+dfrac{1}{3!}+dfrac{1}{4!}+...+dfrac{1}{2023!} 1
Đọc tiếp
Bài 1: Tìm x; y ϵ \(ℤ\)
a) 2x - y\(\sqrt{6}\) = 5 + (x + 1)\(\sqrt{6}\)
b) 5x + y - (2x -1)\(\sqrt{7}\) = y\(\sqrt{7}\) + 2
Bài 2: So sánh M và N
M = \(\dfrac{\dfrac{3}{4}+\dfrac{3}{5}+\dfrac{3}{7}-\dfrac{3}{11}}{\dfrac{6}{4}+\dfrac{6}{5}+\dfrac{6}{7}-\dfrac{6}{11}}\)
N = \(\dfrac{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}}{\dfrac{6}{2}+\dfrac{6}{5}-\dfrac{6}{7}-\dfrac{6}{11}}\)
Bài 3: Chứng minh:
\(\dfrac{1}{2!}+\dfrac{1}{3!}+\dfrac{1}{4!}+...+\dfrac{1}{2023!}< 1\)
tớ hỏi câu này, cho tớ cách làm nka
tìm x biết
\(\sqrt{9+5x^2}+\sqrt{x^4+16}=7-2015x^2\)
thanks m.n