Do \(\hept{\begin{cases}4x^2+12x+9\ge0\forall x\\x^2-4x+4\ge0\forall x\end{cases}}\)
\(\Rightarrow4x^2+12x+9=x^2-4x+4\Rightarrow3x^2+16x+5=0\)
\(\Rightarrow\left(3x^2+15x\right)+\left(x+5\right)=0\Rightarrow\left(x+5\right)\left(3x+1\right)=0\)\(\Rightarrow\orbr{\begin{cases}x=-5\\x=-\frac{1}{3}\end{cases}}\)
Vậy \(x=-5\)hoặc \(x=-\frac{1}{3}\)
1) \(\sqrt{x^2-4x+4}=\sqrt{4x^2-12x+9}\)
2) \(\sqrt{x+2\sqrt{x-1}}=2\)
a) \(\sqrt{x^2-3x+2}=\sqrt{x-1}\)
b) \(\sqrt{x^2-4x+4}=\sqrt{4x^2-12x+9}\)
2) giải pt
3) \(\sqrt{4x+1}=x+1\)
4) \(2\sqrt{x-1}+\dfrac{1}{3}\sqrt{9x-9}=15\)
5) \(\sqrt{4x^2-12x+9}=7\)
6) \(5\sqrt{9x-9}-\sqrt{4x-4}-\sqrt{x-1}=36\)
giúp mk vs ah
\(\sqrt{\left(2x+3\right)^2}=5\)
\(\sqrt{9.\left(x-2\right)^2}=18\)
\(\sqrt{9x-18}-\sqrt{4x-8}+3\sqrt{x-2}=40\)
\(\sqrt{4.\left(x-3\right)^2}=8\)
\(\sqrt{4x^2+12x+9}=5\)
\(\sqrt{5x-6}-3=0\)
giải các phương trình
a/\(\sqrt{x^2-3x+2}=\sqrt{x-1}\)
b/\(\sqrt{x^2-4x+4}=\sqrt{4x^2-12x+9}\)
c/\(\sqrt{x^2-5x+6}=\sqrt{x-2}\)
d/\(\sqrt{4x^2-4x+1}=\sqrt{x^2-6x+9}\)
câu 1:\(\sqrt{7x^2+20x-86}+x\sqrt{31-4x-x^2}=x+1\)
câu 2:\(\sqrt[3]{\frac{12x^2+12x+9}{4}}=x+\sqrt[4]{\frac{4x^3-2}{3}}\)
giải pt\(\sqrt{16-8x+x^2}=4-x\)
\(\sqrt{4x^2-12x+9}=2x-3\)
GPT:
1/ \(\sqrt{7x^2+20x-86}+x\sqrt{31-4x-x^2}=x+1\)
2/ \(\sqrt[3]{\frac{12x^2+12x+9}{4}}=x+\sqrt[4]{\frac{4x^3-2}{3}}\)
tìm gtnn
\(\sqrt{4x^2-4x+1}+\sqrt{4x^2-12x+9}\)
