Các câu hỏi tương tự
Rút gọn:
\(A=\left(\frac{4x\sqrt{x}+3x+9}{x+5\sqrt{x}+6}-\frac{3-\sqrt{x}}{2+\sqrt{x}}\right)\div\left(\frac{\sqrt{x}}{3+\sqrt{x}}-\frac{3+4\sqrt{x}}{x+5\sqrt{x}+6}\right)\)
\(B=\left(x-\sqrt{x}-2\right)\left(\dfrac{3}{\sqrt{x}-2}-\dfrac{4-\sqrt{x}}{x-2\sqrt{x}}\right)\)
Tìm x để B=3A,biếtA=\(\left(\frac{5+2\sqrt{6}}{\sqrt{3}+\sqrt{2}}+\frac{5-2\sqrt{6}}{\sqrt{3}-\sqrt{2}}\right)\) /\(\left(\frac{1}{2\sqrt{5}+3\sqrt{2}}-\frac{1}{2\sqrt{5}-3\sqrt{2}}\right)\)
B=\(\frac{2x^4-x^3+2x^2+x-4}{2x^3-x^2-2x+1}\)
Rút gọn:
\(A=\left(\frac{2+\sqrt{x}}{x-5\sqrt{x}+6}-\frac{\sqrt{x}+3}{2-\sqrt{x}}-\frac{\sqrt{x}+2}{\sqrt{x}-3}\right):\left(2-\frac{\sqrt{x}}{1+\sqrt{x}}\right)\)
x+y4Rightarrowfrac{x+y}{2}2Rightarrowsqrt{frac{x+y}{2}}sqrt{2}P.sqrt{frac{x+y}{2}}sqrt{2}sqrt{x^2+frac{1}{x^2}}+sqrt{2}sqrt{x^2+frac{1}{x^2}}Leftrightarrowsqrt{2}Psqrt{1+1}sqrt{x^2+frac{1}{x^2}}+sqrt{1+1}sqrt{x^2+frac{1}{x^2}}Leftrightarrowsqrt{2}Pge x+frac{1}{x}+y+frac{1}{y}x+frac{1}{x}left(frac{1}{x}+4xright)-3xge4-3xy+frac{1}{y}left(frac{1}{y}+4yright)-3yge4-3yRightarrowsqrt{2}Pge8-3left(x+yright)8-3.4-4đến đay sau răng
Đọc tiếp
\(x+y=4\Rightarrow\frac{x+y}{2}=2\Rightarrow\sqrt{\frac{x+y}{2}}=\sqrt{2}\)
\(P.\sqrt{\frac{x+y}{2}}=\sqrt{2}\sqrt{x^2+\frac{1}{x^2}}+\sqrt{2}\sqrt{x^2+\frac{1}{x^2}}\)
\(\Leftrightarrow\sqrt{2}P=\sqrt{1+1}\sqrt{x^2+\frac{1}{x^2}}+\sqrt{1+1}\sqrt{x^2+\frac{1}{x^2}}\)
\(\Leftrightarrow\sqrt{2}P\ge x+\frac{1}{x}+y+\frac{1}{y}\)
\(x+\frac{1}{x}=\left(\frac{1}{x}+4x\right)-3x\ge4-3x\)
\(y+\frac{1}{y}=\left(\frac{1}{y}+4y\right)-3y\ge4-3y\)
\(\Rightarrow\sqrt{2}P\ge8-3\left(x+y\right)=8-3.4=-4\)
đến đay sau răng
Giải phương trình: \(\frac{\left(x^6+3x^4\sqrt{x^2-x+1}\right)\left(3+x-x^2\right)}{4\left(2+\sqrt{x^2-x+1}\right)\left(x^2-x+1\right)}=\sqrt{x^2-x+1}\left(2-\sqrt{x^2-x+1}\right)\)
Giải phương trình: \(\frac{\left(x^6+3x^4\sqrt{x^2-x+1}\right)\left(3+x-x^2\right)}{4\left(2+\sqrt{x^2-x+1}\right)\left(x^2-x+1\right)}=\sqrt{x^2-x+1}\left(2-\sqrt{x^2-x+1}\right)\)
\(A=\left(\frac{3\sqrt{x}+6}{x-4}+\frac{\sqrt{x}}{\sqrt{x}-2}\right):\frac{x-9}{\sqrt{x}-3}a:Rutgon;b:TìmxđểA=\frac{1}{5}\)
Giải phương trình vô tỉ :
a) \(\left(\sqrt{x+3}-\sqrt{x-1}\right)\left(x^2+\sqrt{x^2+4x+3}\right)=2x\)
b) \(\sqrt{2x+4}-2\sqrt{2-x}=\frac{6x-4}{\sqrt{x^2+4}}\)
c) \(\sqrt{3x^2-4x+2}+\sqrt{3x+1}+\sqrt{2x-1}+6x^3-7x^2-3=0\)
d) \(\sqrt{x^2+15}=3x-2+\sqrt{x^2+8}\)
Bài 1: giải fta)frac{1}{xleft(x+2right)}-frac{1}{left(x+1right)^2}frac{1}{2} b)sqrt{4x^2-x+4}3x+2c)sqrt{x^2-2x+5}x^2-2x-1d)sqrt{8+sqrt{x}}+sqrt{5-sqrt{x}}5e)sqrt{x^2-3x+2}+sqrt{x+3}sqrt{x-2}+sqrt{x^2+2x-3}Bài 2:Tìm nghiệm của fta)x+xy+y9b)x^2+xy+y^2x^2y^2Bài 3:Cho Aleft(frac{sqrt{x}-4x}{1-4x}-1right):left(frac{1+2x}{1-4x}-frac{2sqrt{x}}{2sqrt{x}-1}-1right)a)Rút gọn Ab)Tìm x để AA^2c)Tìm x để /A/1/4
Đọc tiếp
Bài 1: giải ft
a)\(\frac{1}{x\left(x+2\right)}-\frac{1}{\left(x+1\right)^2}=\frac{1}{2}\)
b)\(\sqrt{4x^2-x+4}=3x+2\)
c)\(\sqrt{x^2-2x+5}=x^2-2x-1\)
d)\(\sqrt{8+\sqrt{x}}+\sqrt{5-\sqrt{x}}=5\)
e)\(\sqrt{x^2-3x+2}+\sqrt{x+3}=\sqrt{x-2}+\sqrt{x^2+2x-3}\)
Bài 2:Tìm nghiệm của ft
a)x+xy+y=9
b)\(x^2+xy+y^2=x^2y^2\)
Bài 3:Cho A=\(\left(\frac{\sqrt{x}-4x}{1-4x}-1\right):\left(\frac{1+2x}{1-4x}-\frac{2\sqrt{x}}{2\sqrt{x}-1}-1\right)\)
a)Rút gọn A
b)Tìm x để A>A^2
c)Tìm x để /A/=1/4