Question

\(so\)\(sánh\)

\(99^{20}\)và \(9999^{10}\)

\(3^{21}\)và \(2^{31}\)

\(2^{30}+3^{30}+4^{30}\)và\(3.24^{10}\)

Answer 1

1) \(99^{20}=\left(99^2\right)^{10}=9801^{10}< 9999^{10}\)

2) \(3^{21}=3^{20}\cdot3=9^{10}\cdot3\)

\(2^{31}=2^{30}\cdot2=8^{10}\cdot2\)

mà \(9^{10}\cdot3>8^{10}\cdot2\)=> tự viết tiếp

3) đợi chút

Answer 2

4³⁰ = (4³)¹⁰ = 64¹⁰ > 48¹⁰ = ( 2 . 24 )¹⁰ = ( 2¹⁰ ) . ( 24¹⁰ ) > 3 . 24¹⁰
 => 2³⁰ + 3³⁰ + 4³⁰ > 3 . 24¹⁰

.

Answer 3

*99^20=(90^2)^10=8100^10<9999^10

vậy 99^20<9999^10

*3^21=(3^2)10.3=9^10.3

2^31=(2^3)10.2=8^10.2

9^10.3>8^10.2

Vậy 3^21>2^31