ta co 9^3x=(3^5x)*81^4
=>3^6x=(3^5x)*(3^4)^4
=>3^6x=3^(5x+16)
=>6x=5x+16
=>x=16
ta co 9^3x=(3^5x)*81^4
=>3^6x=(3^5x)*(3^4)^4
=>3^6x=3^(5x+16)
=>6x=5x+16
=>x=16
1.so nghiem cua da thuc x4-x3+x2x la
2.viet so 1993-199 duoi dang tich cua 3 so tu nhien lien tiep so be nhat trong 3 so tu nhien do la
3.tap hop cac gia tri cua x\(\ne\)0 thoa man x3-4x=0 la S(...)
tim so tu nhien x,y thoa man \(x^2-5x+7=3^y\)
tim n thoa man A la so tu nhien :
\(\frac{n^3+8}{n+8}\)
tim tat ca so tu nhien x y thoa man x^2=y^2(x+y^4+2y^2)
neu m,n la cac so tu nhien thoa man
4m^2 + m=5n^2+n thi m - n va 5m+5n+1 deu la so chinh phuong
tim tat ca cac so tu nhien x,y thoa man x^2=y^2(x+y^4+2y^2)
cho a b la 2 so thoa man (a/x+2) +(b/3x-1)=(14x-14)/3x^2+5x-2 vay ab
Cho a, b la cac so tu nhien thoa man 2a2 + a = 3b2 + b. CMR: a - b va 3a+ 3b+ 1 la SCP.
neu m, n la cac so tu nhien thoa man 4m\(^2\)+m = 5n\(^2\)+n thi m-n va 5m +5n +1 la so chinh phuong