\(A=\frac{3}{83}+\frac{7}{84}=\frac{252}{6972}+\frac{581}{6972}=\frac{833}{6972}=\frac{119}{996}\)
\(B=\frac{7}{83}+\frac{3}{84}=\frac{588}{6972}+\frac{249}{6972}=\frac{837}{6972}=\frac{279}{2324}\)
\(\Rightarrow A< B\)
A =\(\frac{3}{83}+\frac{7}{84}\)= \(\frac{119}{996}\)= 0,1194779116
B = \(\frac{7}{83}+\frac{3}{84}\)= \(\frac{279}{2324}\)= 0,1200516351
Suy ra: A < B
\(A=\frac{3}{83}+\frac{7}{84}=\frac{119}{996}\)
\(B=\frac{7}{83}+\frac{3}{84}=\frac{279}{2324}\)
\(\Rightarrow A< B\)