B=\(\frac{2016^{2017}-3}{2016^{2018}-3}\)<1 nên B<\(\frac{2016^{2017}-3+2019}{2016^{2018}-3+2019}\)=\(\frac{2016^{2017}+2016}{2016^{2018}+2016}\)=\(\frac{2016\left(2016^{2016}+1\right)}{2016\left(2016^{2017}+1\right)}\)=\(\frac{2016^{2016}+1}{2016^{2017}+1}\)=A
Vậy A>B
1.So sánh \(\frac{2016}{2017}+\frac{2017}{2018}\)với \(1\)( không tính kết quả )
2.So sánh: \(A=\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}\)và \(B=\frac{2015+2016+2017}{2016+2017+2018}\)
3. Với n là số nguyên dương hãy so sánh 2 phân số sau: \(\frac{n}{n+8}\)và \(\frac{n-2}{n+9}\)
So sánh hai phân số : A=\(\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}\)và B=\(\frac{2015+2016+2017}{2016+2017+2018}\)
So sánh
\(A=\frac{2017^{2016}-2020}{2017^{2016}-6056}\)
\(B=\frac{2017^{2016}+2018}{2017^{2016}-2018}\)
So sánh 2 phân số
A=\(\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}\)
B=\(\frac{2015+2016+2017}{2016+2017+2018}\)
so sanh A va B
\(A=\frac{2017^{100}}{1+2017+2017^2+2017^3+...+2017^{100}}\)
\(B=\frac{2016^{100}}{1+2016+2016^2+2016^3+...+2016^{100}}\)
Câu 1. Tính hợp lý giá trị các biểu thức sau :
a. A = ( 689 - 31 ) - ( 269 - 131 )
b. B = \(\left(\frac{1}{2}+\frac{2016}{2017}+\frac{2017}{2018}+1\right)\times\left(\frac{2016}{2017}+\frac{2017}{2018}+\frac{3}{4}\right)-\left(\frac{1}{2}+\frac{2016}{2017}+\frac{2017}{2018}\right)\times\left(\frac{2016}{2017}+\frac{2017}{2018}+\frac{3}{4}+1\right)\)c. C = \(1-\frac{5}{6}+\frac{7}{12}-\frac{9}{20}+\frac{11}{30}-\frac{13}{42}+\frac{15}{56}-\frac{17}{72}+\frac{19}{90}\)
So sánh hai phân số A=\(\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}\)và B=\(\frac{2015+2016+2017}{2016+2017+2018}\)
Các bn giải giúp mk nha ! Mk cần gấp ! Thanks nhiều. ^-^
so sánh P và Q, biết \(P=\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}\) va \(Q=\frac{2015+2016+2017}{2016+2017+2018}\)
So sánh A=\(\frac{2017^{2017}}{1+2017+2017^2+....+2017^{2016}}\)
B=\(\frac{2016^{2017}}{1+2016+2016^2+...+2016^{2016}}\)
