Question

SO SÁNH:A VÀ B VỚI:

A=\(\frac{116}{339}+\frac{261}{1530}+\frac{121}{445}\)

B=\(\frac{1}{255}+\frac{687}{890}+\frac{2}{226}\)

 

Answer 1

A=\(\frac{113}{139}+\frac{3}{139}+\frac{29}{170}+\frac{121}{445}\)=\(\frac{1}{3}+\frac{1}{133}+\frac{87}{510}+\frac{121}{445}=\frac{1}{3}+\frac{1}{133}+\frac{2}{510}+\frac{85}{510}+\frac{121}{445}\)

=\(\frac{1}{3}+\frac{1}{113}+\frac{1}{255}+\frac{121}{445}+\frac{1}{6}=\frac{1}{113}+\frac{1}{255}+\frac{121}{445}+\frac{1}{2}\)

B=\(\frac{1}{255}+\frac{1}{113}+\frac{242}{890}+\frac{445}{890}=\frac{1}{255}+\frac{1}{113}+\frac{121}{445}+\frac{1}{2}\)

Vậy A=B

Answer 2

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