a)
A = 2002 x 2002
A = ( 2000 + 2 ) x 2002
A = 2000 x 2002 + 2 x 2002
b)
B = 2000 x 2004
B = 2000 x ( 2002 + 2 )
B = 2000 x 2002 + 2 x 2000
Vậy A > B
ta có 2002*2002=(2000+2)*2002=2000*2002+2002*2=2000*2002+4004
2000*2004= 2000*(2002+2)=2000*2002+2000*2=2000*2002+4000
vì 4004>4000
=>a>b
2002 x 2002
= (2000 + 2) x 2002
= 2000 x 2002 + 2 x 2002
2000 x 2004
= 2000 x (2002 + 2)
= 2000 x 2002 + 2000 x 2
Mà 2000 x 2002 + 2 x 2002 > 2000 x 2002 + 2000 x 2 => a > b
a) = \(2002\cdot2002\)
a = \(2002\cdot\left(2002+2\right)\)
a = \(2002\cdot2000+2002\cdot2\)
a = \(2002\cdot2000+4004\)
b) = \(2000\cdot2004\)
b = \(2000\cdot\left(2002+2\right)\)
b = \(2000\cdot2002+2000\cdot2\)
b = \(2000\cdot2002+4000\)
Ta có: 4004 > 4000
\(\Rightarrow2002\cdot2000+4004>2000\cdot2002+4000\)
Do đó a > b