2016^100+2016^99= 2016^99.2016^1+2016^99.1=2016^99.(2016+1)=2016^99.2017
2017^100= 2017^99.2017
Do 2016^99.2017< 2017^99.2017
Nên 2016^100+2016^99< 2017^100
so sánh 2016^100+2016^99 và 2017^100
So sanh A va B biet
A=2017^100/1+2017+2017^2+2017^3+.....+2017^100
B=2016^100/1+2016+2016^2+2016^3+.....+2016^100
so sanh A va B
\(A=\frac{2017^{100}}{1+2017+2017^2+2017^3+...+2017^{100}}\)
\(B=\frac{2016^{100}}{1+2016+2016^2+2016^3+...+2016^{100}}\)
So sánh ps : 2017^99 + 1/2017^100 + 1 và 2017^100 + 1/2017^101 + 1
so sánh 2017^99+1/2017^100+1 và 2017^100+1/2007^101+1
a)Chứng minh rằng: \(\frac{200-\left(3+\frac{2}{3}+\frac{2}{4}+..+\frac{2}{100}\right)}{\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+...+\frac{99}{100}}=2\)
b)\(A=\frac{-21}{10^{2016}}+\frac{-12}{10^{2017}};B=\frac{-12}{10^{2016}}+\frac{-21}{10^{2017}}\)
So sánh A và B
so sánh: A=201799/2017100-2 và B=2017100/2017101-2
A=\(\frac{100^{2015}+1}{100^{2016}+1}\)
B=\(\frac{100^{2016}+1}{100^{2017}+1}\)
So sánh A và B
So sánh :
A = \(\frac{100^{2015}+1}{100^{2016}+1}\) và B = \(\frac{100^{2016}+1}{100^{2017}+1}\)
