Các câu hỏi tương tự
So sánh hai phân số sau:
A=\(\frac{1999^{2002}+1}{1999^{2001}+1}\)
và B=\(\frac{1999^{2001}+1}{1999^{2000}+1}\)
Tìm x,y \(\in Z\):
|x-3|.|x+3|=16
Chứng minh:
\(\frac{1}{2^2}+\frac{1}{4^2}+\frac{1}{6^2}+...+\frac{1}{2016^2}< \frac{1}{2}\)
So sánh:
\(A=\frac{1999^{1999}+1}{1999^{2000}+1}\)và \(B=\frac{1999^{1998}+1}{1999^{1999}+1}\)
TÍNH HỢP LÍa)frac{frac{4}{17}-frac{4}{49}-frac{4}{131}}{frac{-3}{17}+frac{3}{49}+frac{3}{131}}b)frac{-1}{2}+frac{3}{5}+frac{-1}{9}+frac{1}{27}+frac{7}{18}+frac{4}{35}+frac{2}{7}c)frac{3.8.15....9999}{4.9.16.....10000}d)frac{frac{1}{2}+frac{1}{3}+frac{1}{4}+...+frac{1}{2000}}{frac{1999}{1}+frac{1998}{2}+frac{1997}{3}+...+frac{1}{1999}}
Đọc tiếp
TÍNH HỢP LÍ
a)\(\frac{\frac{4}{17}-\frac{4}{49}-\frac{4}{131}}{\frac{-3}{17}+\frac{3}{49}+\frac{3}{131}}\)
b)\(\frac{-1}{2}+\frac{3}{5}+\frac{-1}{9}+\frac{1}{27}+\frac{7}{18}+\frac{4}{35}+\frac{2}{7}\)
c)\(\frac{3.8.15....9999}{4.9.16.....10000}\)
d)\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2000}}{\frac{1999}{1}+\frac{1998}{2}+\frac{1997}{3}+...+\frac{1}{1999}}\)
So sánh:
a) M=\(\frac{1999^{1999+1}}{1999^{2000}+1}và\)N=\(\frac{1999^{1989}+1}{1999^{2009}+1}\)
b) A=\(\frac{-9}{10^{2010}}+\frac{-19}{10^{2011}}và\)B=\(\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
So sánh
\(C=\frac{1999^{2000}+1}{1999^{1999}+1}\)và \(D=\frac{1999^{1999}+1}{1999^{1998}+1}\)
Tính
A=\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+.....+\frac{1}{2000}}{\frac{1999}{1}+\frac{1998}{2}+\frac{1997}{3}+......+\frac{1}{1999}}\)
Ai nhanh và đúng mình tick cho
So sánh : \(\frac{1999×2000}{1999×2000+1}\)và \(\frac{2000×2001}{2000×2001+1}\)
so sánh :
a) \(\frac{3}{124};\frac{1}{41};\frac{5}{207}và\frac{2}{83}\)
b)\(\frac{16}{9}và\frac{24}{13}\)
c)\(\frac{27}{82}và\frac{26}{72}\)
So sánh :
a)\(\frac{3}{124},\frac{1}{41},\frac{5}{207},\frac{2}{83}\)
b)\(\frac{-2525}{2929}và\frac{-217}{245}\)
c)\(A=\frac{3^{10}+1}{3^9+1}vàB=\frac{3^9+1}{3^8+1}\)
d)\(\frac{27}{82}và\frac{26}{75}\)