\(\sqrt{27}\) + \(\sqrt{6}\)> \(\sqrt{35}\)
căn 27 + căn 6 = 7,196156423
căn 35 = 5,916079783
=>căn 27 + căn 6 > căn 35
Ta có: \(\sqrt{27}+\sqrt{6}=\sqrt{6}+3\sqrt{3}=7,64...\)
Và: \(\sqrt{35}=5,91\)
Vì \(7,64>5,91\)
Vậy \(\sqrt{27}+3\sqrt{3}>\sqrt{35}\)
Ủng hộ mik nha!
\(\sqrt{27}+\sqrt{6}\approx5+2\)2.5 = 7,5
\(\sqrt{35}\approx6\) Mà 7,5 > 6
=> \(\sqrt{27}+\sqrt{6}>\sqrt{35}\)