Question

So sánh giá trị của các biểu thức sau:

A=\(\frac{11}{\text{(12+13)}}\) +\(\frac{12}{\text{(13+14) }}\)+\(\frac{13}{\text{(14+12)}}\) ; B= \(\frac{\text{(11+12+13)}}{(12+13+14)}\)

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Answer 1

Ai nhanh được k nha :))

Answer 2

Trả lời 

\(A=\frac{11}{12+13}+\frac{12}{13+14}+\frac{1}{14+15}\)

Hay 

\(A=\frac{11}{12+13}+\frac{12}{13+14}+\frac{13}{14+15}\)

mong xem lại hộ cái 

Answer 3

đề có bị sai không

Answer 4

13 chứ ko phải 1 mk nhầm 

Answer 5

Vì \(\frac{11}{12+13}>\frac{11}{11+12+13}\)

\(\frac{12}{13+14}>\frac{12}{11+12+13}\)

\(\frac{13}{14+12}>\frac{13}{11+12+13}\)

\(\Rightarrow\frac{11}{12+13}+\frac{12}{13+14}+\frac{13}{14+12}>\frac{11+12+13}{12+13+14}\Rightarrow A>B\)

Answer 6

Ta có:\(\frac{11}{12+13}>\frac{11}{12+13+14}\)

          \(\frac{12}{13+14}>\frac{12}{12+13+14}\)

         \(\frac{13}{14+12}>\frac{13}{12+13+14}\)

\(\Rightarrow\frac{11}{12+13}+\frac{12}{13+14}+\frac{13}{14+12}>\frac{11}{12+13+14}+\frac{12}{12+13+14}+\frac{13}{13+14+15}\)

\(\Leftrightarrow A>\frac{11+12+13}{12+13+14}=B\)

Vậy\(A>B\)

Answer 7

Vì \(\frac{11}{12+13}>\frac{11}{12+13+14}\)

\(\frac{12}{13+14}>\frac{12}{12+13+14}\)

\(\frac{13}{14+12}>\frac{13}{12+13+14}\)

Cộng 2 vế tương ứng ta có :

\(\frac{11}{12+13}+\frac{12}{13+14}+\frac{13}{14+12}>\frac{11}{12+13+14}+\frac{12}{12+13+14}+\frac{13}{12+13+14}\)

\(\Rightarrow\frac{11}{12+13}+\frac{12}{13+14}+\frac{13}{14+12}>\frac{11+12+13}{12+13+14}\)

Vậy A > B 

Answer 8

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