Ta có
\(\frac{743}{811}<1\)
\(\frac{3}{2}>1\)
=>\(\frac{743}{811}<\frac{3}{2}\)
Ta có
\(\frac{743}{811}<1\)
\(\frac{3}{2}>1\)
=>\(\frac{743}{811}<\frac{3}{2}\)
So sanh hai phan so:
\(\frac{33.10^3}{2^3.5.10^3+7000}\)Va \(\frac{3774}{5217}\)
so sanh \(\frac{-1}{3}va\frac{4}{5}\)
không tính
So sanh
\(1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{90}+\frac{1}{100}.\)va 100
cac ban giai chi tiet giup mk voi
cho so A=\(\frac{2013+\frac{1}{2}}{\left(2012+\frac{1}{2}\right)^2+2013+\frac{1}{2}}\)
B=\(\frac{2013+\frac{1}{3}}{\left(2012+\frac{1}{3}\right)^2+2013+\frac{1}{3}}\)
so sanh A va B
SO SANH
A=\(\frac{3}{4}+\frac{8}{9}+............+\frac{999}{1000}\)voi 98 va 99
Cho \(A=\left(\frac{1}{^{2^2}}-1\right).\left(\frac{1}{3^2}-1\right).\left(\frac{1}{4^2}-1\right)......\left(\frac{1}{2013^2}-1\right).\left(\frac{1}{2014^2}-1\right)va\)\(B=-\frac{1}{2}.\)Hay so sanh A va B
So sanh: \(\frac{n}{n+1}\)va \(\frac{n+2}{n+3}\)
So sanh :\(\frac{2017}{2018}+\frac{2018}{2019}va\frac{2015}{2016}+\frac{2016}{2017}\)
so sanh 2 PS sau
\(\frac{7^{10}+1}{7^{10}-1}\)va \(\frac{7^{10}-1}{7^{10}-3}\)