Question

so sánh \(\frac{121212}{171717}+\frac{2}{17}-\frac{404}{1717}\)với B=\(\frac{10}{17}\)

Answer 1

\(\frac{121212}{171717}+\frac{2}{17}-\frac{40}{171}\)

\(=\frac{12}{17}+\frac{2}{17}-\frac{4}{17}=\frac{10}{17}\)

\(\Rightarrow A=B=\frac{10}{17}\)

Answer 2

121212/171717 + 2/7 - 40/171

= 12/17 + 2/7 - 4/17 = 10/17

= A = B = 10/17

Answer 3

\(A=\frac{121212}{171717}+\frac{2}{17}-\frac{404}{1717}\)

\(A=\frac{12}{17}+\frac{2}{17}-\frac{4}{17}=\frac{14}{17}-\frac{4}{17}\)

\(A=\frac{10}{17}\)

=> \(A=B\)

Answer 4

\(A=\frac{121212}{171717}+\frac{2}{17}-\frac{404}{1717}\)

\(A=\frac{12}{17}+\frac{2}{17}-\frac{4}{17}\)

\(A=\frac{10}{17}\)

\(\Rightarrow A=B\)