a, \(\frac{-17}{24}< \frac{-25}{31}\)
b,\(\frac{-27}{38}< \frac{-125}{195}\)
c,\(\frac{-22}{111}>\frac{-27}{134}\)
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So sánh các số hữu tỉ:
a) \(\frac{-17}{24}v\text{à}\frac{-25}{31}\)
b) \(\frac{-27}{38}v\text{à}\frac{-125}{195}\)
c) \(\frac{-22}{111}v\text{à}\frac{-27}{134}\)
Bài 1dựa vào tính chất bắc cầu của thứ tự
a,\(\frac{-24}{25}v\text{à}\frac{-23}{27}\)
b,\(\frac{22}{-67}v\text{à}\frac{51}{-152}\)
c,\(\frac{-33}{131}v\text{à}\frac{53}{-217}\)
So sánh các số sau:
a) \(0,5\sqrt{100}-\sqrt{\frac{4}{25}}v\text{à}\left(\sqrt{1\frac{1}{9}}-\sqrt{\frac{9}{16}}\right):5\)
b) \(\sqrt{25+9}v\text{à}\sqrt{25}+\sqrt{9}\)
\(\frac{x}{3}=\frac{y}{4}v\text{à}\frac{y}{3}=\frac{z}{5}v\text{à}x-y+z=32\)
a)\(\frac{z}{5}=\frac{x}{2}=\frac{y}{3}v\text{à}x.y-z=810\)
b)\(5x=3yv\text{à}2x^2-y^2=-28\)
c)\(\frac{x}{2}=\frac{y}{4}=\frac{z}{6}v\text{à}x^2+y^2+z^2=14\)
d)\(x:y:z=3:4:5v\text{à}5z^2-2y^2=594\)
Tìm x, y, z
a, \(\frac{x}{3}=\frac{y}{4};\frac{y}{5}=\frac{z}{7}v\text{à}2\text{x}+3y-z=186\)
b, 3x=2y ; 7y = 5z và x-y+z = 32
c,\(\frac{2\text{x}}{3}=\frac{3y}{4}=\frac{4\text{z}}{5}v\text{à}x+y+z=49\)
d, \(\frac{x^3}{8}=\frac{y^3}{64}=\frac{z^3}{216}v\text{à}x^2+y^2+z^2=14\)
e, x+y=x:y= 3.(x-y)
So sánh:
\(\left(-\frac{1}{5}\right)^{255}v\text{à}\left(-\frac{1}{2}\right)^{579}\)
\(\frac{a}{1}=\frac{b}{4};\frac{b}{c}=\frac{3}{4}v\text{à }4a+b-c=8\)
so sánh \(\frac{1}{101^2}+\frac{1}{102^2}+...+\frac{1}{205^2}v\text{à}\frac{1}{2^2\cdot3\cdot5^2\cdot7}\)