Ta có : \(\frac{a}{b}=\frac{b}{c}=\frac{c}{a}=\frac{a+b+c}{b+c+a}=1\)
==> a=b ; b=c ; c=a ========> a=b=c
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cau 1: Cho A frac{100^{2014}+2}{3}-frac{100^{2015}+17}{9}.tong cac cua so cua B-9ACau 2: So sanh Afrac{1}{1.2}+frac{1}{2.3}+frac{1}{3.4}+........+frac{1}{100.101}voi 1 ta doc A....1Cau 3 : Cho bon so a,b,c,d sao cho a+b+c+d khac 0 . Biet frac{b+c+d}{a}frac{c+d+a}{b}frac{d+a+b}{c}frac{a+b+c}{d}k. Vay kCau 4 : so cac so nguyen am x thoa man x^{2015}left(-2right)^{2014}Cau 5; tim x,y,z biet frac{x}{y}frac{10}{9},frac{y}{z}frac{3}{4}va x-y+z78Cau 6: tap hop cac so co ba chu so chia het cho 18 va to...
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cau 1: Cho A= \(\frac{100^{2014}+2}{3}-\frac{100^{2015}+17}{9}.\)tong cac cua so cua B=-9A
Cau 2: So sanh A=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+........+\frac{1}{100.101}\)voi 1 ta doc A....1
Cau 3 : Cho bon so a,b,c,d sao cho a+b+c+d khac 0 . Biet \(\frac{b+c+d}{a}=\frac{c+d+a}{b}=\frac{d+a+b}{c}=\frac{a+b+c}{d}=k\). Vay k=
Cau 4 : so cac so nguyen am x thoa man \(x^{2015}=\left(-2\right)^{2014}\)
Cau 5; tim x,y,z biet \(\frac{x}{y}=\frac{10}{9},\frac{y}{z}=\frac{3}{4}\)va x-y+z=78
Cau 6: tap hop cac so co ba chu so chia het cho 18 va tong cac chu so ti le voi 1;2;3 la
Cau 7: gia tri cua tong S=1.2+2.3+.....+49.50 la S=
cho\(\frac{a}{b}=\frac{b}{c}=\frac{c}{a}\) va a+b+c khac 0
a] so sanh ac so a,b,c
cho a=2017. tinh b,c
Cho cac so a,b,c va thoa man\(\frac{a}{a+b}+\frac{b}{b+c}+\frac{c}{c+a}=2\)Tinh gia tri bieu thuc \(P=\frac{b}{a+b}+\frac{c}{b+c}+\frac{a}{c+a}\)
cho cac so a,b,c va thoa man \(\frac{ab}{a+b}=\frac{1}{3},\frac{bc}{b+c}=\frac{1}{4},\frac{ca}{c+a}=\frac{1}{5}\)Tinh gia tri bieu thuc P=\(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\)
Cho cac so a,b,c,d thoa man: \(\frac{a}{b+c+d}=\frac{b}{c+d+a}=\frac{c}{d+a+b}=\)
\(\frac{d}{a+b+c}\). Tinh gia tri bieu thuc:
P=\(\frac{a+b}{c+d}=\frac{b+c}{d+a}=\frac{c+d}{b+a}=\frac{d+a}{b+c}\)
a) tim a,b,c biet: \(\frac{a}{-2}\)=\(\frac{b}{3}\);\(\frac{b}{5}\)=\(\frac{c}{4}\)va a+2b+c=32
b) biet so do 3 goc cua mot tam giac ti le voi 4;6;8 tim so do moi goc cua tam giac do?
a,Cho \(\frac{2bz-3cy}{a}=\frac{3cx-az}{2b}=\frac{ay-2bx}{3c}CMR:\frac{x}{a}=\frac{y}{2b}=\frac{z}{3c}\)
b, CHO \(\frac{b+c}{bc}=\frac{2}{a}CMR:\frac{b}{c}=\frac{a-b}{c-a}\)( cac ti so deu co nghia)
so sanh \(\frac{a+n}{b+n}\)và \(\frac{a}{b}\) biết a,b,c thuộc N*
so sanh A B biet A=\(\frac{10^{2018}+1}{10^{2017}+1}\);B=\(\frac{10^{2007}+1}{10^{2008+1}}\)