a)
\(\dfrac{2424}{4848}=\dfrac{2424:2424}{4848:2424}=\dfrac{1}{2}\)
Vậy \(\dfrac{2424}{4848}=\dfrac{1}{2}\)
b)
\(\dfrac{1111}{1212}=\dfrac{1111:101}{1212:101}=\dfrac{11}{12}\)
Mẫu số chung 2 phân số: 12
\(\dfrac{5}{6}=\dfrac{5\cdot2}{6\cdot2}=\dfrac{10}{12}\)
Vì \(10< 11\) nên\(\dfrac{10}{12}< \dfrac{11}{12}\)
Vậy \(\dfrac{5}{6}< \dfrac{1111}{1212}\)
\(\dfrac{2424}{4848}\) và \(\dfrac{1}{2}\)
Ta rút gọn phân số \(\dfrac{2424}{4848}=\dfrac{2424:2424}{4848:2424}=\dfrac{1}{2}\)
Mà \(\dfrac{1}{2}=\dfrac{1}{2}\) nên \(\dfrac{2424}{4848}=\dfrac{1}{2}\)
\(\dfrac{5}{6}\) và \(\dfrac{1111}{1212}\)
Ta rút gọn phân số \(\dfrac{1111}{1212}=\dfrac{1111:101}{1212:101}=\dfrac{11}{12}\)
Ta quy đồng phân số \(\dfrac{5}{6}=\dfrac{5\times2}{6\times2}=\dfrac{10}{12}\)
Mà \(\dfrac{10}{12}< \dfrac{11}{12}\) nên \(\dfrac{5}{6}< \dfrac{1111}{1212}\)
\(\dfrac{2424}{4848}=\dfrac{2424\div2424}{4848\div2424}=\dfrac{1}{2}\) Vậy \(\dfrac{2424}{4848}=\dfrac{1}{2}\)
\(\dfrac{5}{6}=\dfrac{5\times202}{6\times202}=\dfrac{1010}{1212}\) Vậy \(\dfrac{1111}{1212}>\dfrac{5}{6}\)
