2011/2014 < 3012/3015
1010/2019 < 2011/3012
k nha
a)Ta có:1-2011/2014=3/2014
1-3012/3015=3/3015
Vì 3/2014>3/3015 nên 2011/2014<3012/3015
ta thấy:
\(\frac{2011}{2014}+\frac{3}{2014}=1\)
\(\frac{3012}{3015}+\frac{3}{3015}=1\)
mà \(\frac{3}{2014}>\frac{3}{3015}\)=>\(\frac{2011}{2014}< \frac{3012}{3015}\)
vậy.............