\(C=\frac{\left(1.3.5.7...99\right).\left(2.4.6.8...98.100\right)}{2.4.6.8....98.100}=\frac{\left(1.2.3.4...99.100\right)}{\left(1.2\right).\left(2.2\right)\left(3.2\right)...\left(49.2\right).\left(50.2\right)}=\frac{1.2.3.4....99.100}{\left(1.2.3...49.50\right).\left(2.2.2...2\right)}\)
\(C=\frac{\left(1.2.3.4...50\right).\left(51.52.53...100\right)}{\left(1.2.3...50\right)\left(2.2.2....2\right)}=\frac{51}{2}.\frac{52}{2}...\frac{100}{2}=D\)
Vậy C = D