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So sánh
A=\(\frac{2}{60.63}+\frac{2}{63.66}+...+\frac{2}{117.120}+\frac{2}{2003}\)
và B=\(\frac{5}{40.44}+\frac{5}{44.48}+...+\frac{5}{76.80}+\frac{5}{2003}\)
So sánh
A=\(\frac{2}{60.63}+\frac{2}{63.66}+..+\frac{2}{117.120}+\frac{2}{2003}\)
B=\(\frac{5}{40.44}+\frac{5}{44.48}+..+\frac{5}{76.80}+\frac{5}{2003}\)
So sánh
C=\(\frac{2}{60.63}+\frac{2}{63.66}+...+\frac{2}{117.120}+\frac{2}{2006}\)
Và D=\(\frac{5}{40.44}+\frac{5}{44.48}+...+\frac{5}{76.80}+\frac{5}{2006}\)
so sánh
A=\(\frac{2}{60.63}+\frac{2}{63.66}+......+\frac{2}{117.120}+\frac{2}{2017}\)
B=\(\frac{5}{40.44}+\frac{5}{44.48}+........+\frac{5}{76.80}+\frac{5}{2017}\)
So sánh \(A=\frac{2}{60.63}+\frac{2}{63.66}+...+\frac{2}{117.120}+\frac{2}{2006}\)và \(B=\frac{5}{40.44}+\frac{5}{44.48}+...+\frac{5}{76.80}+\frac{5}{2006}\)
17 tháng 8 2021 lúc 15:39
So sánh:
\(A=\dfrac{2}{60.63}+\dfrac{2}{63.66}+.........+\dfrac{2}{117.120}+\dfrac{2}{2003}\)
và \(B=\dfrac{5}{40.44}+\dfrac{5}{44.48}+........+\dfrac{5}{76.08}+\dfrac{5}{2003}\)
So sánh:
A= 2/60.63+2/63.66+....+2/117.120+2/2003
B=5/40.44+5/44.48+...+5/76.80+5/2003
Làm hộ mình nha !
Tính : P = \(\frac{\frac{1}{2003}+\frac{1}{2004}+\frac{1}{2005}}{\frac{5}{2003}+\frac{5}{2004}-\frac{5}{2005}}-\frac{\frac{2}{2002}+\frac{2}{2003}-\frac{2}{2004}}{\frac{3}{2002}+\frac{3}{2003}-\frac{3}{2004}}\)
P=\(\frac{\frac{1}{2003}+\frac{1}{2004}-\frac{1}{2005}}{\frac{5}{2003}+\frac{5}{2004}-\frac{5}{2005}}\)-\(\frac{\frac{2}{2002}+\frac{2}{2003}-\frac{2}{2004}}{\frac{3}{2002}+\frac{3}{2003}-\frac{3}{2004}}\)