Question

So Sánh \(A=\frac{20^{10}+1}{20^{10}-1}\text{và }B=\frac{20^{10}-1}{20^{10}-3}\)

 

Answer 1

A = \(\frac{2^{10}+1}{2^{10}-1}=\frac{2^{10}-1+2}{2^{10}-1}=1+\frac{2}{2^{10}-1}\)

B = \(\frac{2^{10}-1}{2^{10}-3}=\frac{2^{10}-3+2}{2^{10}-3}=1+\frac{2}{2^{10}-3}\)

Vì \(\frac{2}{2^{10}-1}