\(A=\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{2012.2013.2014}\)
\(A=\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{2014-2012}{2012.2013.2014}\)
\(A=\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{2012.2013}-\frac{1}{2013.2014}\right)\)
\(A=\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{2013.2014}\right)=\frac{1}{2}.\frac{2027090}{4054182}\)
\(A=\frac{2027090}{8108364}\)
Ta thấy \(\frac{2027090}{8108364}=0,2499.....\) \(\frac{1}{4}=0,25\)
\(\Rightarrow A< \frac{1}{4}\)