Question

So sánh A=\(\frac{10^{2016}+1}{10^{2017}+1}\)và B=\(\frac{10^{2017}+1}{10^{2018}+1}\)

cứu mình với

Answer 1

ta có: 10A = \(\frac{10^{2017}+1+9}{10^{2017}+1}=1+\frac{9}{10^{2017}+1}\)

10B = \(\frac{10^{2018}+1+9}{10^{2018}+1}=1+\frac{9}{10^{2018}+1}\)

\(vì\frac{9}{10^{2017}+1}>\frac{9}{10^{2018}+1}\) => 10A > 10B => A > B

Answer 2

A > B nhé bn!!!!!!!!!!!!!!

6578

Answer 3

bn đọc kĩ đề đi

Answer 4

nhân A va B voi 10 va rut gon ta co;

9/ 10²⁰¹⁷+1 > 9/10²⁰¹⁸ +1

vay A > B