Ta có :
\(A=\frac{2018^{2017}+1}{2018^{2017}-1}\)
\(\Rightarrow A>\frac{2018^{2017}+1-2}{2018^{2017}-1-2}\)
\(\Rightarrow A>\frac{2018^{2017}-1}{2018^{2017}-3}\)
\(\Rightarrow A>B\)
Vậy \(A>B\)
So sánh:
A= 2018^2017+1/2018^2017-1
B= 2018^2017-1/2018^2017-3
Cho A = 2017 mũ 2018 + 1 phần 2017 mũ 2018 - 3 và b bằng 2017 mũ 2018 - 1 phần 2017 mũ 2018 - 5 hãy so sánh a và b
Cho A= \(\frac{2017^{2018}+1}{2017^{2018}-3}\)
B= \(\frac{2017^{2018}-1}{2017^{2018}-5}\)
Hãy so sánh A với B
Cho
A = \(\frac{2017^{2018}+1}{2017^{2018}-3}\)
B= \(\frac{2017^{2018}-1}{2017^{2018}-5}\)
So sánh A và B
So sánh: A=(20182017 +20172017)2018 và B=(20182018+20172018)2017
so sánh A=\(\frac{2016^{2017}+1}{2017^{2018}+1}\)và B=\(\frac{2017^{2018}+1}{2017^{2017}+1}\)
so sánh:
A=\(\frac{2017^{2018}+1}{2017^{2019}+1}\);B=\(\frac{2017^{2017}+1}{2017^{2018}+1}\)
A=2017^2018+1/2017^2018-3
B=2017^2018-1/2017^2018-5
So sánh:
\(C=\frac{2018^{2019}-1}{2018^{2018}-1}\)và\(D=\frac{2017^{2018}+1}{2017^{2017}+1}\)
