\(\frac{913}{1007}>\frac{913}{2016};\frac{923}{1009}>\frac{923}{2016}\)
\(\Rightarrow A>\frac{913}{2016}+\frac{923}{2016}\)
\(A>\frac{1836}{2016}=B\)
Vậy A>B.
Chúc em học tốt^^
\(A=\frac{2016^{2016}+2}{2016^{2016}-1}\)và\(B=\frac{2016^{2016}}{2016^{2016}-3}\)
So sánh A và B
Giải hộ mk với!!
Sắp xếp từ bé đến lớn các số sau : \(\frac{1005}{2002};\frac{1007}{2006};\frac{1009}{2010};\frac{1011}{2014}\)
\(A=\frac{[(\frac{2}{1001}-\frac{3}{2002})\frac{1001}{17}+\frac{33}{34}]}{[(\frac{7}{1008}+\frac{11}{2016})\frac{1008}{25}+\frac{1009}{2016}]}\)
A=\(\frac{[\left(\frac{2}{1000}-\frac{3}{2002}\right)\frac{1001}{17}+\frac{33}{44}]}{[\left(\frac{7}{1008}+\frac{11}{2016}\right)\frac{1008}{25}+\frac{1009}{2016}]}\)
So sánh
\(\frac{a}{b}\)và \(\frac{a+2016}{b+2016}\)(với a<b)
So sánh:
A=\(\frac{2015}{\sqrt{2016}}+\frac{2016}{\sqrt{2015}}\) và B=\(\sqrt{2015}+\sqrt{2016}\)
so sánh
a) \(\frac{2016}{2017}\)và\(\frac{2017}{2018}\)
b)\(\frac{2017}{2016}\)và\(\frac{2018}{2017}\)
A = (\(\frac{1}{1009}+\frac{1}{1010}+.....+\frac{1}{2015}+\frac{1}{2016}\)) :(\(\frac{1}{1}-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2015}-\frac{1}{2016}\))
\(\sqrt{17}+\sqrt{26}+1và\sqrt{99}\)
b)chứng minh:\(\frac{1}{\sqrt{ }1}+\frac{1}{\sqrt{ }2}+\frac{1}{\sqrt{ }3}+...+\frac{1}{\sqrt{ }99}+\frac{1}{\sqrt{ }100}>10\)
c)cho:S=\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2013}-\frac{1}{2014}+\frac{1}{2015}\)vàP=\(\frac{1}{1008}+\frac{1}{1009}+\frac{1}{1010}+...+\frac{1}{2014}+\frac{1}{2015}\)tính \(\left(S-P\right)^{2016}\)
