Ta có :
\(\frac{2015}{2016}>\frac{2015}{2016+2017}\)
\(\frac{2016}{2017}>\frac{2016}{2016+2017}\)
\(\Rightarrow\frac{2015}{2016}+\frac{2016}{2017}>\frac{2015+2016}{2016+2017}\)
\(\Rightarrow A>\frac{2015+2016}{2016+2017}\)
\(\Rightarrow A>B\)
Chúc bạn học tốt !!!
\(A=\frac{2015}{2016}+\frac{2016}{2017}\) \(B=\frac{2015+2016}{4033}\)
\(A=\frac{2015}{2016}+\frac{2016}{2017}\) \(B=\frac{2015}{4033}+\frac{2016}{4033}\)
\(\Rightarrow A>B\)
ta có : B=2015+2016/2016+2017
=2015/2016 + 2016/2017
Vì 2015/2016 + 2016/2017 = 2015/2016 + 2016/2017
suy ra A=B
Ta có:
\(B=\frac{2015+2016}{2016+2017}=\frac{2015}{2016+2017}+\frac{2016}{2016+2017}\)
Ta thấy \(\frac{2015}{2016}>\frac{2015}{2016+2017};\frac{2016}{2017}>\frac{2016}{2016+2017}\)
\(\Rightarrow A>B\)
Vậy A>B
\(A=\frac{2015}{2016}+\frac{2016}{2017}\)
\(A=\frac{4064255+4064256}{4066272}=\frac{8128511}{4066272}\) > 0
\(B=\frac{2015+2016}{2016+2017}=\frac{4031}{4033}< 0\)
VAY : A > B
