Question

So sánh A và B

A = 10^19 + 1 / 10^20 + 1

B = 10^20+1 / 10^21 + 1

(dấu gạch ở trên là phần)

 

Answer 1

Ta có: A=\(\frac{10^{20}+1}{10^{21}+1}\)< 1 => \(\frac{10^{20}+1+9}{10^{21}+1+9}\)<1 => \(\frac{10^{20}+1+9}{10^{21}+1+9}\)​​ =  \(\frac{10^{20}+10}{10^{21}+10}\)=\(\frac{10.\left(10^{19}+1\right)}{10.\left(10^{20}+1\right)}\)=\(\frac{10^{19}+1}{10^{20}+1}\)=>B<A

Answer 2

A=B =1/10

Answer 3

A=B=1/10