A=2018.(2017+1)=2017.2018+2018
B=2017.2019=2017.(2018+1)=2017.2018+2017
vì 2018>2017
=>A>B
\(A=2018.2018=\left(2017+1\right).2018\) \(=2017.2018+2018\)
\(B=2017.2019=2017.\left(2018+1\right)\) \(=2017.2018+2017\)
Vậy từ đó \(\Rightarrow A>B\)
Ta có : B = 2017.2019
= (2018 - 1).(2018 + 1)
= 2018.2018 + 2018 - 2018 - 1
= 2018.2018 - 1 < 2018.2018 = A
=> B < A hay A > B
A = 2018.2018 = (2017 +1).2018 = 2017.2018 + 2018
B = 2017.2019 = 2017.(2018 + 1) = 2017.2018 + 2017
Vì 2017 < 2018 nên A > B
A=2018.2018=2018.(2017+1)=2018.2017+2018
B=2017.2019=2017.(2018+1)=2018.2017+2017
vì 2018>2017
=>A>B
hok tốt :v.
Ta có : 2017.2019=(2018-1).(2018+1) hay =2019.2017=(2018+1).(2018-1) =[2018.(2018-1)]+[1.(2018-1)] =(2018.2018-2018)+(1.2018-1) =2018.2018-2018+2018-1 =2018.2018-1<2018.2018. Vậy: B<A hay A>B. ~よくべんきょうする~