Ta có công thức :
\(\frac{a}{b}< 1\) \(\Rightarrow\) \(\frac{a}{b}< \frac{a+c}{b+c}\)
\(\Rightarrow\)\(B=\frac{15^{16}+1}{15^{17}+1}< \frac{15^{16}+1+14}{15^{17}+1+14}=\frac{15^{16}+15}{15^{17}+15}=\frac{15\left(15^{15}+1\right)}{15\left(15^{16}+1\right)}=\frac{15^{15}+1}{15^{16}+1}=A\)
Vậy \(A>B\)
tại sao a/b<1 thì a/b<a+c/b+C