Question

So sánh A và B A= 2003x2004-1/2003x2004.                     b=2004x2005-1/2004x2005.                                                        

Giúp mình mình cần gấp

Answer 1

#)Giải :

Ta có :

\(A=\frac{2003\times2004-1}{2003\times2004}=\frac{2003\times2004}{2003\times2004}-\frac{1}{2003\times2004}=1-\frac{1}{2003\times2004}\)

\(B=\frac{2004\times2005-1}{2004\times2005}=\frac{2004\times2005}{2004\times2005}-\frac{1}{2004\times2005}=1-\frac{1}{2004\times2005}\)

Vì \(\frac{1}{2003\times2004}>\frac{1}{2004\times2005}\)

\(\Rightarrow A>B\)

Answer 2

+) \(A=\frac{2003\times2004-1}{2003\times2004}\)

   \(=\frac{2003\times2004}{2003\times2004}-\frac{1}{2003\times2004}\)

    \(=1-\frac{1}{2003\times2004}\)

+) \(B=\frac{2004\times2005-1}{2004\times2005}\)

    \(=\frac{2004\times2005}{2004\times2005}-\frac{1}{2004\times2005}\)

    \(=1-\frac{1}{2004\times2005}\)

+) Vì 2004 x 2005 > 2003 x 2004 

=>  \(\frac{1}{2004\times2005}< \frac{1}{2003\times2004}\)

=> \(1-\frac{1}{2004\times2005}>1-\frac{1}{2003\times2004}\)

Vậy B > A

Answer 3

A=2003x2004 - 1/2003x2004=2003x2004/2003x2004 - 1/2003x2004=1 - 1/2003x2004

B=2004x2005 - 1/2004x2005=2004x2005/2004x2005 - 1/2004x2005=1 - 1/2004x2005

Vì 1=1 và 1/2003x2004 > 1/2004x2005 nên 1-1/2003x2004 < 1-1/2004x2005

Vậy B < A

Answer 4

MÌnh ấn nhấm B > A