\(A=\frac{54.107-53}{53.107+54}=\frac{54.107+54-107}{\left(54-1\right).107+54}=\frac{54.\left(107+1\right)-107}{54.107-107+54}=\frac{54.108-107}{54.\left(107+1\right)-107}=\frac{54.108-107}{54.108-107}=1\)
\(B=\frac{135.296-133}{134.269+135}=\frac{135.296+135-268}{\left(135-1\right).269+135}=\frac{135.\left(296+1\right)-268}{135.269-269+135}=\frac{135.297-268}{135.\left(269+1\right)-269}=\frac{135.297-268}{135.270-269}>1\)
\(\Rightarrow A< B\)
\(A=\frac{54.107-53}{53.107+54}=\frac{53.107+107-53}{53.107+54}=\frac{53.107+54}{53.107+54}=1\)
\(B=\frac{135.296-133}{134.269+135}=\frac{134.296+296-133}{134.269+135}=\frac{134.296+163}{134.269+135}\)
Vì \(134=134;296>269\Rightarrow134.269< 134.296\)mà\(163>135\Rightarrow134.269+135< 134.296+163\)hay \(B>1\)
Ta có \(A=1;B>1\Rightarrow A< B\)
chị ơi e tính ra là phân số đầu tiên lớn hơn nhưng k chắc có đúng k nữa
có A=\(\frac{54.107-53}{53.107+54}\)=\(\frac{53.107+107-53}{53.107+54}\)=\(\frac{54.107+54}{54.107+54}\)=1
tg tự, tính B rồi so sánh
ngu như pò mới giải đc câu này