\(2^{225}=8^{75}< 9^{75}=3^{150}\)
\(2^{91}>2^{90}=32^{18}>25^{18}=5^{36}>5^{35}\)
\(99^{20}=\left(99.99\right)^{10}< \left(99.101\right)^{10}=9999^{10}\)
a, \(2^{225}=\left(2^3\right)^{75}\)
\(3^{150}=\left(3^2\right)^{75}\)
b,\(2^{91}=\left(2^{13}\right)^7\)
\(5^{35}=\left(5^5\right)^7\)
c,\(99^{20}=\left(99\cdot99\right)^{10}\)
\(9999^{10}=\left(99\cdot101\right)^{10}\)
a, 2225 = ( 23 )75 = 875
3150 = ( 32 )75 = 975
Vì 875 < 915
=> 2225 < 3150
Vậy ...
b, 291 > 290
Mà 290 = 3218 và 3218 > 2518
25 18 = 536 và 536 > 535
=> 291 > 290 > 2518 > 535
=> 291 > 535
Vậy ...
c, 9920 = ( 992 )10 = 980110
Mà 9801 < 9999
=> 980110 < 999910
=> 9920 < 999910
Vậy ...
Hok tốt
