a) ta thay : \(2^{10}=2^{10}\)
\(3^{20}=\left(3^2\right)^{10}=9^{10}\)
vi \(2< 9\)nen \(2^{10}< 9^{10}\)
vay \(2^{10}< 3^{20}\)
b) \(2.5^3=250\)
\(5.2^3=40\)
vi \(250>40\) nen \(2.5^3>5.2^3\)
vay \(2.5^3>5.2^3\)
\(2^{30}=\left(2^3\right)^{10}=8^{10}\)
\(3^{20}=\left(3^2\right)^{10}=9^{10}\)
vi \(8< 9\) nen \(8^{10}< 9^{10}\)
vay \(2^{30}< 3^{20}\)